Class 11Chemistry8-3.Organic Chemistry : Purification and characterizationChemical analysis of organic compounds
EasyHow is the silver halide obtained from an organic compound distinguished?
(N/A) $i$. White precipitate: Chlorine is present,and these precipitates are more soluble in $NH_4OH$.
$ii$. Light yellowish precipitate: Bromine is present. The precipitate is sparingly soluble in ammonium hydroxide and becomes soluble upon heating.
$iii$. Yellow precipitate: It is insoluble in $NH_4OH$,indicating the presence of iodine.
$ii$. Light yellowish precipitate: Bromine is present. The precipitate is sparingly soluble in ammonium hydroxide and becomes soluble upon heating.
$iii$. Yellow precipitate: It is insoluble in $NH_4OH$,indicating the presence of iodine.
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What can be inferred if a blood-red color is obtained in the Lassaigne's test?
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View SolutionAppearance of blood red colour,on treatment of the sodium fusion extract of an organic compound with $FeSO_4$ in presence of concentrated $H_2SO_4$ indicates the presence of element/s
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View SolutionMatch column $-I$ and column $-II$ with the correct relation:
Column $-I$ Column $-II$ $(i).$ Prussian blue $(a).$ Presence of phosphorus $(ii).$ Yellow precipitate $(b).$ Presence of sulphur $(iii).$ Purple solution $(c).$ Presence of nitrogen $(iv).$ Black precipitate $(d).$ Presence of chlorine
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|---|---|
| $(i).$ Prussian blue | $(a).$ Presence of phosphorus |
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| $(iv).$ Black precipitate | $(d).$ Presence of chlorine |
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View SolutionThe organic compound that gives the following qualitative analysis is:
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| $b$. $NaOH$ solution | Soluble |
| $c$. $Br_2/\text{water}$ | Decolourization |
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